Nov 13, 2016 · The answer is log_2(27) To solve this problem we need the inverse operation of exponents: logarithms. If 2 raised to some power x is equal to 27, then the logarithm of base 2 and an argument of 27 is equal to x.

Jul 16, 2016 · x = 3 and x = 0 We can rewrite 9x^2 = 27x by subtracting 27x from both sides and make it equal to 0. 9x^2 = 27x 9x^2 - 27x = 0 Factoring out a 9 and x we now get 9x(x-3) = 0 We now have two separate factors, namely 9x = 0 and x-3 = 0, so we can simply solve for x. 9x = 0 -> x = 0 x-3=0 -> x =3 So our solutions are x = 3 and x = 0.

Jul 22, 2015 · More simply, x=6 (logarithms are unnecessary in this case). 81=3^{4} and 27=3^{3}, so this equation can also be written as 3^{4x}=3^{3(x+2)}=3^{3x+6}. Since the bases are now the same, we can equate exponents to get 4x=3x+6 so that x=6 (technically this equating of exponents requires the fact that exponential functions (with base not equal to 1 ...

Mar 13, 2018 · Raise to the power of 2/3 hence 27^(3/2)=(x^(2/3))^(3/2) 27^(3/2)=x x = (27^(1/2) )^3 x = (3sqrt(3))^3 = 81sqrt(3)

May 23, 2015 · x^2 -12x+27=0 We can Split the Middle Term of this expression to factorise it and thereby find the solution. In this technique, if we have to factorise an expression like ax^2 + bx + c, we need to think of 2 numbers such that: N_1*N_2 = a*c = 1*27 = 27 And N_1 +N_2 = b = -12 After trying out a few numbers we get N_1 = -9 and N_2 =-3 9*3 = 27 and -9+(-3)= -12 x^2 …

Jun 11, 2017 · x=6 "change the "color(blue)"base "" from " 9 to 3 rArr(3^2)^x=(3^3)^(x-2) rArr3^(2x)=3^(3x-6) "since the bases are the same, we can equate the exponents" rArr3x-6=2x rArrx=6

Feb 13, 2017 · You can also use logarithmic functions, if you have a logarithm table or at least a calculator that can do log functions, if not complex exponential ones.

Apr 13, 2018 · Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than...

Jun 16, 2016 · The answer is x=-5 3^(x-4)=27^(x+2) First step is to write 27^(x+2) as the power of 3 3^(x-4)=3^(3(x+2)) Now you can write this equation as the equation of exponents: x-4=3(x+2) x-4=3x+6 x-3x=6+4 -2x=10 x=-5

Aug 19, 2015 · color(blue)(x=-3 9^(2x)=27^(x−1 We know that 9=3^2 27=3^3 So, 3^(2(2x))=3^(3(x−1) 3^(4x)=3^(3x−3 ...