Apr 17, 2016 · sqrt((5+x)(5-x)) sqrt(25-x^2)=sqrt((5+x)(5-x))

Apr 15, 2015 · You must apply x=5/costheta and do the mathematics step by step. This integral does not seem solvable by other techniques, e.g. integration by part, just integration by …

Apr 10, 2018 · Solution: -5 <= x <= 5 or [-5,5] 25-x^2 >= 0 or (5+x)(5-x)>=0 Critical points are 5+x=0 or x= -5 and 5-x=0 or x= 5 f(x)=0 when x=-5 and x=5 Sign chart: When x< -5 ...

Jan 13, 2018 · When we write: f(x) = (25-x^2)^(1/2) we normally require 25-x^2 >= 0 and as a result say that the domain of f(x) is [-5, 5]. This is what I would call an implicit domain, i.e. a …

Jul 29, 2015 · Notice how sqrt(25 + x^2) prop sqrt(a^2 + x^2), which implies x = atantheta with a = 5. If we let: x = 5tantheta dx = 5sec^2thetad theta sqrt(25 + x^2) = sqrt(5^2 + 5^2tan^2theta) = …

Jul 31, 2016 · How do you integrate #int x^2/sqrt(25-x^2)# using trig substitutions? Calculus Techniques of Integration Integration by Trigonometric Substitution 1 Answer

Apr 6, 2015 · How do you find the integral of #x*sqrt(25+x^2)#? Calculus Techniques of Integration Integration by Trigonometric Substitution. 2 Answers

Nov 1, 2016 · How do you evaluate the limit #(x^2-25)/(x^2-4x-5)# as x approaches 5? Calculus Limits Determining Limits Algebraically. 1 Answer

Jan 26, 2017 · How do you find the domain and range of #sqrt(25-x^2) #? Algebra Expressions, Equations, and Functions Domain and Range of a Function. 1 Answer

Jan 27, 2015 · Let's work on the radical and rewrite it in the following way: sqrt(a-bx^2)=sqrt(a[1-b/a x^2])=sqrt(a[1-(sqrt(b/a) x)^2])=sqrt(a)sqrt(1-(sqrt(b/a) x)^2) Now, if sin theta = sqrt(b/a) x, …