
How do you simplify #sqrt (25-x^2)#? - Socratic
2016年4月17日 · sqrt((5+x)(5-x)) sqrt(25-x^2)=sqrt((5+x)(5-x))
What is the integral of #x*sqrt(25+x^2)#? - Socratic
2015年7月29日 · Notice how sqrt(25 + x^2) prop sqrt(a^2 + x^2), which implies x = atantheta with a = 5. If we let: x = 5tantheta dx = 5sec^2thetad theta sqrt(25 + x^2) = sqrt(5^2 + 5^2tan^2theta) = 5sectheta Then we get: = int 5tantheta*5sectheta*5sec^2thetad theta = 125int tanthetasecthetasec^2thetad theta Then, if we let: u = sectheta du = secthetatanthetad theta …
How do you factor x^2 + 25 completely? - Socratic
2016年1月21日 · In the given expression #x^2+25# we note that the discriminant #sqrt(b^2-4ac)# is a negative quantity. As such the quadratic has only imaginary roots. These can be calculated and factors found as
How do you solve 25-x^2>=0? - Socratic
2018年4月10日 · Solution: -5 <= x <= 5 or [-5,5] 25-x^2 >= 0 or (5+x)(5-x)>=0 Critical points are 5+x=0 or x= -5 and 5-x=0 or x= 5 f(x)=0 when x=-5 and x=5 Sign chart: When x< -5 ...
How do you factor x^2-25? - Socratic
2015年5月2日 · The answer is (x+5)(x-5) . (x^2-25) fits the pattern of the difference of squares in which (a^2-b^2)=(a+b)(a-b).
How do you integrate sqrt(x^2-25)/x? + Example - Socratic
2015年4月15日 · You must apply x=5/costheta and do the mathematics step by step. This integral does not seem solvable by other techniques, e.g. integration by part, just integration by trigonometric substitution. On integration by trigonometric substitution, you either apply trigonometry or trigonometric functions, such as the one herein. Unfortunately there is no …
Using trigonometric substitution to integrate $\\int\\frac{x^3dx ...
2020年12月9日 · I thought your $(25-x^2)^{3/2}$ was in the denominator, which is why I got a different value from you. I've edited it to reflect your work. I checked my final answer, and it's the same as yours, just factorized differently. $\endgroup$ –
calculus - $y= (25-x^2)^ {1/2},\;y=3$ find the volume
$\begingroup$ Oh thank you, should I write the integral from -4 to 4 of $25-x^2 -3^2$ $\endgroup ...
algebra precalculus - How to solve $\sqrt{49-x^2}-\sqrt{25-x^2}=3 ...
2018年7月29日 · I recognize the two difference of squares: $49-x^2$ and $25-x^2$. I squared the equation to get: ${49-x^2}-2(\\sqrt{(49-x^2)(25-x^2)})+{25-x^2}=9$ However, I can't quite figure out how to remove the
How to interpret $x^2= 25-y^2$ - Mathematics Stack Exchange
2021年4月5日 · For a circle with radius of $5$, we know it is, $$x^2 + y^2 = 25.$$ I can interpret it as $f(x,y) = x^2+y^2$ and $g(z)=25$, the final circle is when the two graph ...