2016年4月17日 · sqrt((5+x)(5-x)) sqrt(25-x^2)=sqrt((5+x)(5-x))

2015年7月29日 · Notice how sqrt(25 + x^2) prop sqrt(a^2 + x^2), which implies x = atantheta with a = 5. If we let: x = 5tantheta dx = 5sec^2thetad theta sqrt(25 + x^2) = sqrt(5^2 + …

2016年1月21日 · In the given expression #x^2+25# we note that the discriminant #sqrt(b^2-4ac)# is a negative quantity. As such the quadratic has only imaginary roots. These can be …

2018年4月10日 · Solution: -5 <= x <= 5 or [-5,5] 25-x^2 >= 0 or (5+x)(5-x)>=0 Critical points are 5+x=0 or x= -5 and 5-x=0 or x= 5 f(x)=0 when x=-5 and x=5 Sign chart: When x< -5 ...

2015年5月2日 · The answer is (x+5)(x-5) . (x^2-25) fits the pattern of the difference of squares in which (a^2-b^2)=(a+b)(a-b).

2015年4月15日 · You must apply x=5/costheta and do the mathematics step by step. This integral does not seem solvable by other techniques, e.g. integration by part, just integration by …

2020年12月9日 · I thought your $(25-x^2)^{3/2}$ was in the denominator, which is why I got a different value from you. I've edited it to reflect your work. I checked my final answer, and it's …

$\begingroup$ Oh thank you, should I write the integral from -4 to 4 of $25-x^2 -3^2$ $\endgroup ...

2018年7月29日 · I recognize the two difference of squares: $49-x^2$ and $25-x^2$. I squared the equation to get: ${49-x^2}-2(\\sqrt{(49-x^2)(25-x^2)})+{25-x^2}=9$ However, I can't quite figure …

2021年4月5日 · For a circle with radius of $5$, we know it is, $$x^2 + y^2 = 25.$$ I can interpret it as $f(x,y) = x^2+y^2$ and $g(z)=25$, the final circle is when the two graph ...