(3k + 1)(3k + 2)(3k + 3) = 3(3k + 1)(3k + 2)(k + 1) since k is an element of Z, it follows that (3k + 1)(3k + 2)(k + 1) is an element in Z, this and our definition of divisible gives us the desired result.

Factor 3 out of the third factor and we have (3k+1)(3k+2)3(k+1), so one of its factors is 3, which means 3 divides it. The other way. For any n consecutive integers, exactly one of them must be divisible by n.

Question 1144114: if k+1,2k-1, 3k+1,are three consecutive terms of a geometric progression, find the possible values of the common ratio? please help me to show the workings in full. Answer by ikleyn(52254) (Show Source):

Algebra -> Sequences-and-series-> SOLUTION: .Find k so that the numbers 2k+1, 3k+4, and 7k+6 form a geometric sequence Log On Algebra: Sequences of numbers, series and how to sum them Section Solvers Solvers

Question 981570: 1.Find k so that the numbers 2k+1, 3k+4, and 7k+6 form a geometric sequence 2.Glenn bought a car for Php600,000. The yearly depreciation of his car is 10% of its value at the start of the year. What is its value after 4 years? 3.During a free-fall, a skydiver jumps 16 feet, 48 feet, and 80 feet on the

You can put this solution on YOUR website!-18-6k=6(1+3k)...given:-18-6k=6+18k.....distributing the right side:

Question 1175058: find k so that 2k+1, 3k+1 and 5k+1 form a geometric sequence Answer by ikleyn(52114) ( Show Source ): You can put this solution on YOUR website!

You can put this solution on YOUR website! When what is the value of ? Write as so everything will be a fraction.

You can put this solution on YOUR website! Start with the given equation. Add to both sides. Subtract from both sides.

For tutors: simplify_cartoon( 5*(2k+6)+2*(1-3k)=60 ) If you have a website, here's a link to this solution.