2016年6月1日 · Here's a concept map that shows how to get from any of these to the other. [Really, the only things you need to remember are:

2018年4月20日 · In a hydroxide #(OH^-)# ion, we see that the total charge of the ion is #-1#. That means, the total sum of the oxidation numbers of the elements present in the ion totals out to be #-1#. The ion has one oxygen atom and one hydrogen atom. Hydrogen is less electronegative than oxygen, and so will possess its usual #+1# state.

2014年5月8日 · The pH + pOH = 14 The pOH = -log[OH-] The pH is measure of acidity of a solution whereas the pOH is a measure of basicity of a solution. The two expressions are opposites expressions. As the pH increases the pOH decreases and vice versa. Both values equal 14. To convert a concentration of into pH or pOH take the -log of molar concentration of the hydrogen ions or the molar concentration of the ...

2017年6月10日 · #vecmu_(OH)= "1.5 D"# is a derived quantity that requires you to already have measured #"1.85 D"# for the overall dipole moment of water. You aren't required to know how to calculate it; you would be given either #vecmu_(t ot)# for the overall molecule, the percent ionic character, or #vecmu# for one bond.

2018年4月15日 · In this context, the brackets means "concentration"... It is tempting to assume that HO^- and H_3O^+ are actual species in aqueous species.

2018年7月18日 · This is misleading, because they all become more soluble in #"NH"_4"OH"(aq)#. #"AgI"# seems to be the least soluble mainly because it has the most covalent character, and the two atoms have the most similar atomic radii in context, …

2018年2月18日 · Well look at defining reaction.... "Acid + Base "rightleftharpoons" Conjugate base + conjugate acid" And so we got.... underbrace(NH_3(aq))_"base" + H_2O(l ...

2017年5月26日 · Where #OH^-) and CV^+# are the concentration of them in M. We know that the concentration of NaOH is 0.1M or the #OH^- # concentration is 0.1M as 1 mol of NaOH contributes 1 mole of #OH^-# because it is a strong base. The equation for dissociation in water #"NaOH" + "H"_2"O" rightleftharpoons "Na"^+ + "OH"^-# Plug in the new found variable

2016年6月17日 · You'll need two equations for this: #\mathbf("pH" = -log["H"^(+)])# #\mathbf("pH" + "pOH" = 14)# So, all you need to do is take the negative base-10 logarithm of the ...

Balancing a redox reaction requires identifying the oxidation numbers in the net ionic equation, breaking the equation into half reactions, adding the electrons, balancing the charges with the addition of hydrogen or hydroxide ions, and then completing the equation.