2009年10月23日 · Use Work-Energy Theorem, Loss in K.E. = Work done against friction 1/2 (m1 + m2) v^2 - 0 = (mu)Nx where (mu) is the coefficient of kinetic friction; N is the Normal reaction by the table to the 8 kg block.. and N = 8g and x is the distance traveled by the block before it …

2021年5月17日 · Perhaps it would be useful to formulate the work energy theorem here. Assume we have a system of particles ##m_1,\ldots,m_N## with position vectors ##r_1,\ldots,r_N## relative an inertial frame. A net force that the particle ##m_i## experiences is presented as follows

2011年8月2日 · Is there some initial Kinetic Energy? As to the work-energy theorem. The conservation of energy is the most infallible and fundamental tenets of physics. However, in the world of blocks and springs the truth of the work-energy theorem relies on this notion of a "rigid object" an infinitely incompressible thing.

2016年4月4日 · The general work–energy theorem states that the work done on a system by external forces equals the change in energy of the system. This energy may come in the form of (1) overall kinetic energy, (2) internal potential energy, or (3) internal kinetic energy (heat falls into this category, because it’s simply the random motion of molecules).

2017年1月22日 · Your "technique" is just to apply the conservation of energy (or the work-energy theorem) which is used throughout physics and is extensively documented. The relation $\tan\theta=x_2/x_1$ is a simple geometrical constraint, it is …

2008年10月11日 · My professor gave us two types of formulas for the work energy theorem, stating that there are more and each will get progressively better and designed for use on more situations. The first one we got, and the one most high school students receive, is: W = delta (K), where W is work and the RHS is the change in kinetic energy. The second ...

2020年4月13日 · The above is consistent with the work-energy theorem which only addresses the effect of the net work done on an object, namely to change its kinetic energy. The source(s) of the energy for performing the net work is irrelevant. Hope this helps.

2024年3月15日 · The work energy theorem says that the spring is not gaining KE. The "total work" is the sum of the work from each force. The wall has a displacement of zero, so the wall's work is $0$. The hand has a work of $\int F \ ds$, which from Hooke's law is $1/2 \ k x^2$, assuming that the spring started at

2024年7月27日 · I believe your confusion stems from a misapplication of the Work-Energy Theorem. Work is only equal to change in kinetic energy if no potential fields are present (i.e. the Work-Energy Theorem only applies for free, rigid bodies). Gravity is one of these fields, so it is possible to do work without altering kinetic energy."

2024年9月26日 · But the issue arises when I attempt to apply work energy theorem on the blocks independently. Here's what I did. Taking only block A as the system. $1/2 kx^2 = 1/4 mv^2$ (taking horizontal velocity only) This gives me the wrong answer. Spring potential energy depends on deformation in the spring. So for each of the blocks it should be $1/2kx^2 ...