
The value of 2cos10° + sin100° + sin1000° + sin10000° is (A) O (B ...
2023年7月1日 · 8. We know that sin100° = sin(90° + 10°) = sin10° because the sine function has a periodicity of 360°. Therefore, our expression simplifies to: 2cos10° + sin10° - sin40° + sin80° 9. Now, let's consider the values of sin10°, sin40°, and sin80°. These angles fall within the first quadrant, where the sine function is positive.
[Best Answer] cos10°+sin10°/cos10°-sin10°=cot35° - Brainly.in
2015年11月4日 · Hi , LHS = ( Cos 10 + Sin 10 ) / ( Cos 10 - Sin 10 ) { Multiply numerator and and denominator with 1 / Cos 10 }
Sin10+sin20+sin40+sin50=sin70+sin80 - Brainly
2017年6月11日 · Sin10+sin20+sin40+sin50=sin70+sin80 Get the answers you need, now! PranshuNidhi PranshuNidhi 12.06.2017 ...
Find the value of sin10*sin20*sin30*sin40*sin50*sin60*sin70
2024年10月4日 · Find an answer to your question find the value of sin10*sin20*sin30*sin40*sin50*sin60*sin70*sin80*sin90 sabarmathin sabarmathin 04.10.2024
Find the value of sin10sin20sin30sin40sin50sin60sin70sin80sin90
2021年9月22日 · Answer: The value of is . Step-by-step explanation: Given: We need to find the value of this . We know that . So we get as
Prove that sin 50 - sin 70+ sin 10 = 0 - Brainly.in
2019年1月22日 · Click here 👆 to get an answer to your question ️ Prove that sin 50 - sin 70+ sin 10 = 0
The value of cos40° sin10°is - Brainly
2024年1月27日 · Click here 👆 to get an answer to your question ️ the value of cos40° sin10°is ronychakraborty4916 ronychakraborty4916 27.01.2024
Prove that sin10°sin30°sin50°sin70°=1/16 - Brainly.in
2017年9月15日 · Click here 👆 to get an answer to your question ️ Prove that sin10°sin30°sin50°sin70°=1/16 vaishnavikalesh9679 vaishnavikalesh9679 15.09.2017
The value of cos40°+sin10°is - Brainly
2019年7月20日 · The value of cos40°+sin10°is - 11349051. Trigonometry: Trigonometry is the study of relations between angles and their ratios with various properties to find sine, cosine, tan, cosec, sec and cot ratios.
2sin theta = root 3cos10 + sin10 Please please ans - Brainly.in
2019年7月27日 · A trigonometric equation 2sin θ = √3cos10 + sin10. To Find, The value of this θ. Solution, The given expression is . 2sin θ = √3cos10 + sin10. sin θ = √3/2cos10 + 1/2sin10. Now, we know that. sin 60 = √3/2. cos 60 = 1/2. Now, substituting the values. sin θ = sin60*cos10+cos60*sin10. sin θ = sin (60+10) ( sin(a+b) = sina*cosb ...