2013年8月8日 · The Oberon edition is available as a free PDF, but the PL/0 chapter was removed and expanded into a second book (also free online), Compiler Construction. This expanded book uses a more robust language called Oberon-0, which includes arrays, records, types, etc.

2011年8月12日 · Constants are expressions with a fixed value. Literals are the most obvious kind of constants. They are used to express particular values within the source code of a program.

2016年1月27日 · So pp[0] points to the address of p, which is 0x2000, and by dereferencing I would expect to get the contents of address 0x2000

2014年3月27日 · I am having a hard time making my PL/SQL code work. I have a constraint that makes sure 5 digits have been input. The constraint works for any number that does not use a 0 first. Example 0, 1, 2, 3...

2016年1月6日 · I am selecting id where it cannot be equal to 0, nor can the value be (null). I wrote: WHERE id IS NOT NULL (+) and id not in ('0') I got 2 errors Error(9,5): PL/SQL: SQL Statement ignored

2011年10月10日 · Given the following EBNF grammar (found on wikipedia for PL/0), what is an expression preceded by the "ODD" keyword? I would like to implement the simple language as a small project but I can not ...

2018年1月13日 · Assuming the assignment is to exclude all strings that consist entirely of zero's, at most one decimal point and possibly leading and/or trailing spaces, here is one way to do it, which requires only standard string functions (and therefore should be faster than any regular-expression solution).

2014年12月22日 · 0L is a long integer value with all the bits set to zero - that's generally the definition of 0.The ~ means to invert all the bits, which leaves you with a long integer with all the bits set to one.

2016年12月7日 · Spacing utilities that apply to all breakpoints, from xs to xxl, have no breakpoint abbreviation in them. This is because those classes are applied from min-width: 0 and up, and thus are not bound by a media query.

2014年12月8日 · OV = 0 UP = 0 EI = 1 PL = 0 ZR = 0 AC = 0 PE = 0 CY = 0 After the 3 instructions. OV = 0 UP = 0 EI = 1 PL = 0 ZR = 1 AC = 0 PE = 1 CY = 0 Where the flags registers are as defined here. Interpreted as Parity Set, Carry not set, zero is set, sign is not set, overflow is not set. Which seems to corroborate YOUR solution.