2016年6月25日 · =sinx(1/sinx - sinx) =sinx((1 - sin^2x)/sinx) =cancel(sinx)(1 - sin^2x)/cancel(sinx) =cos^2x

"The fundamental trigonometric identities" are the basic identities: •The reciprocal identities •The pythagorean identities

2018年3月7日 · color(green)(=> 1 sin x * csc x = sin x * (1 / sin x) using fundamental identities. cancel( sin x )* (1 / cancel (sin x) ) = 1

2018年6月7日 · How do you prove #csc x - sin x = cos x cot x#? Trigonometry Trigonometric Identities and Equations Proving Identities. 2 Answers

2018年2月20日 · 1 csc(theta) is the reciprocal of sin(theta), meaning that csc(theta)=1/sin(theta) sin(theta) * 1/sin(theta) = sin(theta)/sin(theta)=cancel(sin(theta))/cancel(sin ...

2016年5月18日 · How do you simplify #csc θ sin θ#? Trigonometry Trigonometric Identities and Equations Fundamental ...

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2017年4月16日 · yes, 1/sin^2x=csc^2x We know that sinx=1/cscx and we also know that sinxsinx=1/cscx1/cscx and so we can say sin^2x=1/csc^2x and also 1/sin^2x=csc^2x

2016年9月30日 · Since #cot theta=cos theta/sin theta and csc theta =1/sin theta#, the expression becomes: #(cos theta/sin theta)/(1/sintheta-sin theta)#

2015年10月21日 · #csc(x) = (sin(x))^(-1) = 1/sin(x)# is the reciprocal of the #sin# function. I think some of the blame for this confusion has to lie with the common convention of writing #sin^2(x)# to mean #sin(x)^2#. So when you have #csc(x) = 1/sin(x) = sin(x)^(-1)# you might think that we would also write that as #sin^(-1)(x)#, but that's reserved for # ...