2018年7月30日 · $\mathrm{atm \cdot L}$ is a derived unit for energy. Pressure is defined as being force/area, and volume is distance cubed. Pressure is defined as being force/area, and volume is distance cubed. If you multiply out the units of these quantities, you can see it is equivalent to force times distance, i.e. work , measured in energy.

2019年11月22日 · Generally, you can work with any units you like; however, this requires the use of conversion factors. The use of conversion factors is never required when only coherent SI units are used; therefore, the use of coherent SI units (the SI base units and the SI coherent derived units, including those with special names) are preferred.

2023年5月11日 · Use whichever value of R has the most common units to help avoid stoichiometry. But you have to use the units as written. Also you misread the table. Should be first two divided by second two. Not all 4 multiplied. So R has to be written as a constant in the units of 0.0821(L * atm / K * mol) “0.0821 Latm/Kmol” You cant use 0.0821. But also ...

2017年5月14日 · As $\pu{atm}$ is a multiple of $\pu{N//m^2}$ and $\pu{L}$ is a multiple of $\pu{m^3}$, then $\pu{L atm}$ is a measure of joules, the unit of energy, which is $\pu{kg m^2//s^2}$ in base SI units. Share

2019年1月3日 · Also both of them are ratios of respective quantities [ ratio of molarity(s) in Kc and ratio of pressure(s) in Kp], so they should be dimensionless according to dimensional analysis. But in some places I have seen units mentioned along with both Kc and Kp. It is quite confusing and I don't see any uniformity in this. Anyone please help.

2015年10月30日 · General Gas Constant, $\mathcal{R} = 0.0821\:\mathrm{dm^3\cdot atm\cdot K^{-1} mol^{-1}}$ General Gas Constant, $\mathcal{R} = 1.989\:\mathrm{cal\cdot K^{-1} mol^{-1}}$

2015年4月8日 · The two units torr, and mm of Hg were the same until they were redefined. The torr was named after the Italian Evangelista Torricelli. 1 atmosphere is $101325\ \mathrm{Pa}$. The torr is defined as $1/760$ of an atmosphere. This is equal to $133.322\overline{368421052631578947}~\mathrm{Pa}$, which periodically infinitely repeats.

2015年6月6日 · The standard change in free energy, which is used to determine the equilibrium constant Kp is based on the pure reactants at 1 atm going to pure products at 1 atm. Therefore, the partial pressure must be expressed in atm in order to be consistent with Kp. This essentially normalizes the partial pressure by 1 atm.

2021年7月1日 · This contradiction occurs due to the difference in the units of the solubility product. This all sums back to the elementary teaching, "Don't compare things with different units." We can mathematically compare only the concentration of products and not their equilibrium constants if they have different units.

2016年2月18日 · The exponent can also be derived from the stoichiometric coefficients as shown above. In the special case that the exponent is zero the unit of measurement is 1, i.e. neither Pa, nor atm, nor Torr, or any other unit of pressure measurement. $\endgroup$ –