The absolute value function takes any term and transforms it to its non-negative form. Therefore, we must solve the term within the absolute value function for both its negative and positive equivalent. Solution 1 x + 4 = -6 x + 4 - color (red) (4) = -6 - color (red) (4) x + 0 = -10 x = -10 Solution 2 x + 4 = 6 x + 4 - color (red) (4) = 6 - color (red) (4) x + 0 = 2 x = 2 The Solutions Are: …

2016年11月10日 · Solving and keeping the equation balanced gives: 6x −4 = 20 6x −4 +4 = 20+ 4 6x −0 = 24 6x = 24 6 ⋅ x 6 = 24 6 (6 6) ⋅ x = 4 1 ⋅ x = 4 x = 4

2016年10月10日 · -6x-24 Distribute the -6 throughout the set of parenthesis. Meaning, multiply -6 to each term within the parenthesis. -6xxx = -6x and -6xx4 = -24 -6x-24

2016年4月17日 · x= (ln ( (1+sqrt (5))/2))/ (ln (3/2)) Divide by 4^x to form a quadratic in (3/2)^x.

2016年9月4日 · We have: 6x − 4 = 3x + 2 Let's subtract 3x from both sides of the equation: ⇒ 3x − 4 = 2 Then, let's add 4 to both sides: ⇒ 3x = 6 Finally, to solve for x, let's divide both sides by 3: ⇒ x = 2

2019年4月17日 · How do I formally show the radius of convergence of the Taylor series of f(x) = x 6 − x 4 + 2 at a = − 2?

Restricted Access. We may pursue legal actions over unauthorized uses of this API.\"Get

2018年7月16日 · 7 − 3(x −4)1 +5(x − 4)2 If you had been asked to find the approximation of f (x) at x = 4.3, you could now just plug in x = 4.3 into this, giving the approximation:

2015年10月19日 · Can anyone tell me how to solve this? $x^6-x^5+x^4-x^3+x^2-x+1=0$ What I got to was $x^7+1=0$. Thanks in advance.

You can simplify polynomials only if they have roots. You can think of polynomials as numbers, and of monomials of the form (x-a) as prime numbers. So, as you can write a composite numbers as product of primes, you can write a "composite" polynomial as product of monomials of the form (x-a), where a is a root of the polynomial. If the polynomial has no roots, it means that, in a …