2016年11月30日 · How do you solve #x^3-1=0#? Precalculus Complex Numbers in Trigonometric Form Powers of Complex Numbers. 1 ...

2025年2月27日 · 7 – 4 + 3 x 0 + 1 = ? The author is challenging what the average person knows. The correct answer is, of course, 4. So many people out there insist that it's 1. After all, anything times 0 is 0. I've even seen some people claim the answer is 7, but I suspect that's a matter of glossing over the details and mistaking the multiplication for ...

2017年4月24日 · See below. For my approach, I will be using a graphical interpretation. You can rewrite the equation as x^3 - x - 1 = 0 as the first step. Then graph the following: f(x) = x^3 - x - 1. graph{x^3 - x - 1 [-10, 10, -5, 5]} Click on where the graph intersects the x-axis. This point should be (1.325, 0). Therefore, the answer is x = 1.325.

2016年11月27日 · x=1,x=-3/2 2x^2+x-3=0 Solve by factoring: 2x^2-2x+3x-3=0 2x(x-1)+3(x-1)=0 (2x+3)(x-1)=0 2x+3=0 2x=-3 x=-3/2 x-1=0 x=1

2018年1月30日 · After trial and error, we see that #(2,0)# is the #x#-intercept. We now divide #x^3+x-10# by #x-2# to get #x^2+2x+5# We now try to find the #x# intercept of #x^2+2x+5# .

How do you divide #(3.0 x 10^4)/ (7 x 10^-7) #? Do you subtract the exponents when dividing numbers that include scientific notation? How do you express #90000/0.03# in scientific notation and then divide using the rules of exponents?

2017年8月11日 · See below. Making the substitution u(x) = 1/(y(x)) and u'(x) = -1/(y^2(x)) y'(x) we have ( (1 + x) u^2 + 2 x u u'-6)/(2 x u^3)=0 and now supposing that 2 x u^3 ne 0 we have (1 + x) u^2 + 2 x u u'-6 = 0 Now making z = u^2 we have the new linear differential equation x z'+(1+x)z-6=0 This differential equation can be easily solved giving z =1/x(6-C e^-x) where and then u = …

2017年6月13日 · Solution for (x+3)/(x-1) >= 0 is the region (-oo,-3]uu[1.oo) i.e. {x:x<=-3 or x>=1} The sign of (x+3)/(x-1) depends on the values (x+3) and (x-1) take at any point. It is apparent that change of sign will appear around x=-3. Observe before that (x+3) is negative and after that it is positive. Similarly, before x=1, (x-1) is negative and after that it is positive. Now, leave the …

2017年12月23日 · -1/6. Suppose that "the Reqd. Limit L="lim_(x to 0)(sinx-x)/x^3. Substiture x=3y," so that, as "x to 0, y to 0

2017年10月11日 · graph{3*x^0 [-10, 10, -5, 15]} The derivative of a function can also be viewed as the slope of that function at a certain point in time. Since a constant value is graphed as a straight line and never moves up or down, the slope will always be #0# .