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How do you solve the system \displaystyle{2}{x}+{7}{y}={8} and \displaystyle{x}+{5}{y}={7} using substitution?

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x^{2}-x-6=0 -x+3\gt 2x+1 ; line\:(1,\:2),\:(3,\:1) f(x)=x^3 ; prove\:\tan^2(x)-\sin^2(x)=\tan^2(x)\sin^2(x) \frac{d}{dx}(\frac{3x+9}{2-x}) (\sin^2(\theta))' \sin(120)

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2024年4月14日 · To solve 2 x + 5 = − 27, subtract 5 from both sides to isolate 2 x which gives 2 x = − 32. Dividing both sides by 2 results in x = − 16 . Hence, the final answer is x = − 16 .

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