
SOLUTION: Find the X intercept and the y intercept without …
4y=2x-1 Found 2 solutions by Alan3354, rothauserc: Answer by Alan3354(69443) (Show Source): You can put ...
Algebra Solver and Math Simplifier that SHOWS WORK
Welcome to Graphical Universal Mathematical Expression Simplifier and Algebra Solver (GUMESS). It solves most middle school algebra equations and simplifies expressions, and it SHOWS ALL WORK.
SOLUTION: graph linear equation y = 2x - 1 - Algebra Homework …
Question 151365: graph linear equation y = 2x - 1 Answer by jim_thompson5910(35256) (Show Source):
describe the relationship between the graph of y=2x +1 and it's ...
For every (a,b) on y=2x+1, if you project horizontally to y=x then vertically to Y=(1/2)X-1/2 you will find it meets the reflection at X=b, and Y=a. Black line: Green line:
SOLUTION: Simplify square root of x^2+2x+1 - Algebra …
Question 416287: Simplify square root of x^2+2x+1 Answer by jsmallt9(3758) (Show Source):
SOLUTION: Graph this equation 3 ways 2x+3y=1 - Algebra …
You can put this solution on YOUR website! Graph this equation 3 ways 2x+3y=1 1. Make a table of values of x and y.
SOLUTION: What is the solution of |2x - 1| = 5 ? 2x-1=5 2x=5+1 …
2x - 1 = 5 >>transpose 2x = 5 + 1 >>add 2x = 6 >>divide the equation by two 2x/2 = 6/2 x = 3 >>we are not ...
SOLUTION: Find the solution of the exponential equation.. 3^2x …
3^(2x-1) = 5 you really need parentheses to remove any doubt as to which part of the expression is in the exponent and which part isn't. based on what i think it is, the solution would be: take the log of both sides of the equation to get: log(3^(2x-1)) = log(5) this becomes: (2x-1) * log(3) = log(5) divide both sides of the equation by log(3 ...
SOLUTION: Find three ordered pairs that satisfy the equation. y
You can put this solution on YOUR website! y = 2x - 1 For x = -1, 0 and 1, y = 2(-1) - 1 = -3 y = 2(0) - 1 = -1 y = 2(1) - 1 = 1
SOLUTION: Graph the following linear equation: y=-2x-1 Any help …
Question 102647: Graph the following linear equation: y=-2x-1 Any help with this one would be great. Thank you so much.