2015年10月21日 · 17x^2-12x=0 The general form of the quadratic equation is: ax^2+bx+c=0 in this case we have: 17x^2=12x=> subtract 12x from both sides: 17x^2-12x=0=> in general form …

2015年12月27日 · x = +-sqrt(17) ~~ +-4.123 The equation x^2 = 17 has two solutions, which are the square roots of 17. The principal square root of 17 is the positive one, which is what we …

2015年4月29日 · Write it as: x^2-10x=-8 add and subtract 25; x^2-10x+25-25=-8 (x-5)^2-25=-8 (x-5)^2=17 x-5=+-sqrt(17) x_(1,2)=5+-sqrt(17)

#17x^2-12x=0# this is now in the form: #ax^2+bx+c=0# With: #a=17# #b=-12# #c=0# That can be used in the quadratic formula to get your two Real solutions (if possible) for #x# as: #x_(1,2)=( …

2016年4月5日 · x+5, remainder = 3 Look at the first terms of the divisor and the dividend, x and x^2. When x is multiplied by x, we get x^2. This x is the first term of the quotient. This x is …

2015年11月2日 · No real roots This can be written as x^2 = -17 x = +-sqrt(-17) Well you have 2 possible complex root but they are real

-3, -14 x^2 + 17x +42 = 0 or, x^2 + 14x + 3x +42 = 0 or, x(x + 14) + 3 (x + 14) = 0 or, (x + 3)(x+14) = 0 or, x= -3, -14

2016年8月30日 · The Soln. Set ={(1,4),(-4,-1)}. Sub.ing y=x+3 in the first eqn. to get. x^2+(x+3)^2=17, or, 2x^2+6x+9-17=0, i.e., x^2+3x-4=0 rArr (x-1)(x+4)=0 rArr x=1, x=-4.

Note that #52 = 13xx4# and #17 = 13+4# So: #x^2+17x+52 = (x+13)(x+4)# In general we find #(x+a)(x+b) = x^2+(a+b)x+ab# So if we can find a pair of numbers #a, b# whose product is the …

2015年5月3日 · 8x^2-17x+2 Look for integer factoring: "Factors (ignoring signs) of " 8 = {(1,8),(2,4)} "Factors (ignoring signs) of " 2 ={(1,2)} Checking for a combination that adds up to …