2015年8月16日 · # x^2+2x−15=0# We can Split the Middle Term of this expression to factorise it and thereby find solutions.. In this technique, if we have to factorise an expression like #ax^2 + bx + c#, we need to think of 2 numbers such that:

2017年4月29日 · Solution : x= 1/2(1 + sqrt(31)) and x= 1/2(1 - sqrt(31)) 2x^2 =2x+15 or 2x^2 -2x= 15 or 2(x^2-x) =15 or (x^2-x) = 15/2or (x^2-x +(1/2)^2) -1/4= 15/2 or (x-1/2)^2 = 15 ...

2015年10月17日 · Factor y = 15x^2 - 2x - 8 Ans: y = (3x + 2)(5x - 4). I use the new AC Method to factor trinomials (Socratic Search). y = 15x^2 - 2x - 8 = 15(x + p) (x + q) Converted y' = x^2 - 2x - 120 = (x + p')(x + q'). p' and q' have opposite signs.

2016年7月15日 · #x(x+15)=0# Because the product is 0, one of the two factors must be equal to 0. Either #x = 0, or x+ 15 =0," in which case " x = -15# This gives two solutions, exactly what we expect with a quadratic.

2017年1月3日 · x^2+25x+150=(x+10)(x+15) We want to look for two numbers. These numbers should have a product of color ...

You can put this solution on YOUR website! The given equation is in the form y = ax^2 + bx + c We see that only a = -15 is known while b and c are currently unknown

2016年6月26日 · 15x^2-x-2=(3x+1)(5x-2) To factorize a quadratic polynomial ax^2+bx+c, if the discriminant b^2-4ac is a square f a rational number, then one can factorize it by splitting b in two parts whose product is ac.

2016年6月16日 · 15x^2-x-2=(3x+1)(5x-2) To factorize 15x^2-x-2 by grouping, we have to first split coefficient of middle term -1 in two parts so that their product is the product of coefficient of other two i.e. 15xx(-2)=-30.

2015年8月5日 · Factor y = 15x^2 - 19x + 6 Ans: (5x - 3)(3x - 2) y = 15x^2 - 19x + 6 = 15(x - p)(x - q). I use the new AC Method (Yahoo, Google Search) Converted trinomial y' = x^2 ...

2018年5月21日 · x=-3 or x =-5 Multiply everything by x^2 to remove the fractions. x^2xx8/x +x^2xx15/x^2=x^2xx-1 (8x^2)/x +(15x^2)/x^2=-x^2 8x+15=-x^2 Add x^2 to both sides x^2+8x+15=0 Factorise (x +3)(x +5)=0 x +3=0 or x +5=0 x=-3 or x=-5