How do you factor x^2+13x+12? - Socratic
2018年5月24日 · #"the factors of + 12 which sum to + 13 are + 12 and + 1"# #x^2+13x+12=(x+12)(x+1)# Answer link. Jacobi J.
How do you solve the inequality 2x^3 + 13x^2 -8x - Socratic
2015年12月15日 · Here, a = 2, b = 17 and c = 26. x = (-b +- sqrt(b^2 - 4ac))/(2a) = (-17 +- sqrt(17^2 - 4*2*26))/(4) " "= (-17 +- 9)/4 Thus, your second and your third roots are x = -2 and …
How do you find the value of c that makes x^2-13x+c into a
2017年4月13日 · 169/4 Half the coefficient of x which would be -13/2 and then square it which would be 169/4 which 'c' should be equal to. The perfect square would be (x-13/2)^2
How do you find the limit of #(5x^2-8x-13)/(x^2-5)# as x
2015年3月6日 · Use the properties of limits. lim_(xrarr3)(x^2-5)=lim_(xrarr3)x^2-lim_(xrarr3)5 (Subtraction property) =(lim_(xrarr3)x)^2-lim_(xrarr3)5 (Power property) =3^2-5 (Limits of …
How do you factor 2x^{2}-13x+24? - Socratic
2017年8月11日 · Step 3: Divide the numbers by the leading coefficient (#2#) #(x-16/2)(x+3/2)# Step 4: If the numbers divide “evenly” then this is the factor. If the numbers canNOT divide …
How do you factor x^4 - 13x^2 - 30? - Socratic
x^4-13x^2-30 = (x^2-15)(x^2+2) = (x-sqrt(15))(x+sqrt(15))(x^2+2) x^4-13x^2-30 is quadratic in x^2. To factor it, first find a pair of factors of 30 whose difference is 13. Such a pair is 15 and 2. …
How do you factor x^-4 -13x^-2 +36 =0? - Socratic
2015年5月6日 · x=+-1/2, +-1/3 Multiply by x^4 to give 36x^4-13x^2+1 Solve using the quadratic formula for x^2 x^2=(13 ...
How do you factor x^3 + 13x^2 + 42x? - Socratic
2016年7月4日 · #= x [x^2 + 13x + 42]# Now getting the factors of 42 and seeing if the sum of its factors equals to 13 ( middle value). By getting its factors ( #7*6# = 42) we have come to know …
How do you write 2y+3=-1/3(x-2) in standard form? - Socratic
2017年10月21日 · First, standard form is ax+by+c=0 In this question, we can expend the formula and rearrange it. You can try it first, and the steps are as follow: Step 1: Expend it 2y+3= …
How do you solve the quadratic using the quadratic formula given …
2017年2月15日 · +-2 i and +-3 i x^4 + 13 x^2 + 36=0 assuming y = x^2, (x^2)^2 + 13 x^2 + 6 =y^2+13y+36=0 using y = (-b +- sqrt(b^2-4ac))/(2a), where a=1, b=13 and c=36 y = (-13+-sqrt ...