2013年11月13日 · Given the equation y = m*x + b, where m is the slope and b is the y-intercept, you already have y, m, and x (just plug in X1, Y1), so you can solve for b. – Reinstate Monica - …

Convert (x1, y1, x2, y2) coordinates to (center_x, center_y, width, height). If you're using PyTorch, Torchvision provides a function that you can use for the conversion:

2017年9月16日 · y1 returns a bessel function of order 1. It is not reserved, but it is defined in math.h. Even if you don't include math.h, it is defined as a built-in function by the compiler …

You can use the rank of a matrix (i.e. a 2D array) to determine whether its columns (interpreted as lists of coordinates) are collinear: Its rank is one, if and only if all the points are collinear with …

2012年11月6日 · Get the tangent by subtracting the two points (x2-x1, y2-y1). Normalize it and rotate by 90 degrees to get the normal vector (a,b) . Take the dot product with one of the …

2016年4月7日 · x1 are the x coordinates of the points for the first line, y1 are the y coordinates for the same -- the elements in x1 and y1 must be in sequence. x2 and y2 are the same for the …

2015年5月19日 · I want to draw graph using a list of (x,y) pairs instead of using two lists, one of X's and one of Y's. Something like this: a = [[1,2],[3,3],[4,4],[5,2]] plt.plot(a, 'ro') Rather than: plt

2011年4月27日 · public static void drawLine (double x1, double y1, double x2, double y2) { ((Graphics2D)g).draw(new Line2D.Double(x0+x1*scale, y0-y1*scale, x0+x2*scale, y0 …

2013年4月29日 · Ask questions, find answers and collaborate at work with Stack Overflow for Teams. Try Teams for free Explore Teams

public static double distance (double x0, double y1, double x1, double y0) { return Math.hypot(x1-x0, y1-y0); // <-- From your link. The formula for finding the distance between two points is …