2017年4月26日 · See the solution process below: First, add color(red)(c) to each side of the equation to isolate the x term while keeping the equation balanced: ax - c + color(red)(c) = b + color(red)(c) ax - 0 = b + c ax = b + c Now, divide each side of the equation by color(red)(a) to solve for x while keeping the equation balanced: (ax)/color(red)(a) = (b + c)/color(red)(a) …

2015年4月1日 · ax^2 + bx +c = 0 Divide all terms by a so as to reduce the coefficient of x^2 to 1 x^2 +b/a x + c/a=0 Subtract the constant term from both sides of the equation x^2+b/a x = - c/a To have a square on the left side the third term (constant) should be (b/(2a))^2 So add that amount to both sides x^2 +b/a x +(b/(2a))^2 = (b/(2a))^2 - c/a Re-write the left-side as a square …

the quadratic equation itself is (standard form) ax^2 + bx + c = 0 where: a is the coefficient of the x^2 term b is the coefficient of the x term c is the constant term you use the a,b,c terms in the quadratic formula to find the roots. the minimum / maximum point of the quadratic equation is given by the formula: x = -b/2a

2018年4月16日 · How do you determine the amount of liquid a paper cone can hold with a 1.5-inch diameter and a

y = (c - ax)/b NOTE: y = (-ax + c)/b is the same thing as y = (c - ax)/b. We can apply the commutative rule of addition on the numerator allowing us to switch the terms around not changing the value of the entire fraction.

Find the derivative of y=bx^2 + ax + c. Assume b,a, and c are constants.We have y^1 = Your solution’s ready to go! Enhanced with AI, our expert help has broken down your problem into an easy-to-learn solution you can count on.

Math; Advanced Math; Advanced Math questions and answers; 1.27. Consider the congruence ax ≡ c (mod m). (a) Prove that there is a solution if and only if gcd(a, m) divides c. (b) If there is a solution, prove that there are exactly gcd(a, m) distinct solutions modulo m.

A first-order differential equation is called separable provided that f(x,y) can be written as dy dx + P(x)y = Q(x). dy If y = ax + by + c, then 11 dy Thus, for the substitution v= ax + by + C, dx dy Substitute v and dx in the given differential equation = Fax +by+c) to get dx Rearrange the equation found in the previous step to isolate the v ...

Since "c" is negative number, change the sign of the inequality to the opposite one. You will get ax + b >= bc. Next, subtract "b" from both sides of the last inequality.

2016年4月22日 · y=(c-ax)/b The aim in solving for y is to get y on one side by itself: ax+by=c by=c-ax y=(c-ax)/b