
volume calculus problem - Math Help Forum
2008年12月3日 · The base of S is an elliptical region with boundary curve 9x^2 + 4y^2=36. Cross sections perpendicular to the x-axis are isosceles right triangles with hypotenuse in the base. …
Find d^2y/dx^2 in terms of y and x. | Math Help Forum
2014年9月26日 · The second reply's answer was correct, so I'm not sure if the first replier was solving for something else. Or just for y in terms of x.
Solving polynomials with terms of 3 | Math Help Forum
2015年6月25日 · I'm having trouble solving the following question: "The specifications for a cardboard box state that the width is 5 cm less than the length, and the height the is 1 cm …
value of ( p+ q )r - Math Help Forum
2012年9月9日 · If x^4 + 4x^3 + 6px^2 + 4qx + r is divisible by x^3 + 3x^2 + 9x + 3, the value of (p + q) r is? anybody help me on this?..
Calculus... | Math Help Forum
2008年2月28日 · 2(4-x)=0. From this you can easily tell at the point x=4 the tangent is horizontal. Firstly, the line y=33x have a slope of 33, but remember the slope is the same as a value of a …
ellipse inscribed in a rectangle | Math Help Forum
2008年11月7日 · To determine the equation of an ellipse inscribed in a rectangle of vertices A(4,3),B(4,-3),C(-4,3),D(-4,-3) Answer: 9x^2+4y^2=36
Optimization: A Wire is to be cut into Two Pieces.
2010年3月28日 · 2) Please seek opportunities to simplify your life. Rather than your last step, notice that \pi is a factor of both Numerator and Denominator and eliminate it, leaving only 4\pi …
How is this done? - Math Help Forum
2010年3月11日 · Find a polynomial of positive degree in Z9[x] that is a unit. I'm a bit confused here, I know a unit is an element a such that au=1=ua, but I don't know how to find a …
y = sqrt {1 + (9x/4)} dx...Arc Length - Math Help Forum
2014年4月29日 · y = x^(3/2) - 1 over [0,1]. Let INT be the integral symbol. I was able to construct the integral but after plugging the limits x = 0 to x = 1, I get a different answer every time. Here …
find constants - Math Help Forum
2010年5月18日 · find constants a,b, and c such that the graph of f(x)=x^3+ax^2+bx+c will increase to the point (-3,18), decrease to the point (1,-14) and then continue increasing …