
How much force is needed to accelerate a 66 kg skier at 2 m/s^2 ...
2016年8月13日 · How much force is needed to accelerate a #66# #kg# skier at #2# #m##/s^2#? Physics. 1 Answer
Question #09ac6 - Socratic
2016年5月29日 · In your case, gold is said to have an enthalpy of fusion equal to #"67 kJ kg"^(-1)#. This tells you that in order to melt #"1 kg"# of gold, i.e. go from solid gold at its melting to …
How to calculate the anhydrous ammonia, from Kg to normal
2018年1月23日 · How to calculate the anhydrous ammonia, from Kg to normal cubic metre in the gas state?
Consider the 65.0 kg ice skater being pushed by two others
2017年3月12日 · A = F/m = 30.44/65.0 = 0.468 ms^{-2} That is the correct answer in physics. So much the worse for whoever wrote the question is not the answer they have set! The initial …
The heat of vaporization of water is 40.66 kJ/mol. How much
2016年11月16日 · "6.48 kJ" The molar heat of vaporization, DeltaH_"vap", sometimes called the molar enthalpy of vaporization, tells you how much energy is needed in order to boil 1 mole of …
How do you calculate the density in g/mL of 2.0 L of ... - Socratic
2016年9月2日 · 9466 views around the world You can reuse this answer ...
What is the magnitude of the gravitational force a 67.5 kg
2017年4月2日 · Newton's law of gravitation states that the gravitational force between two objects is given by F=G(m_1m_2)/r^2, where G is the gravitational constant (~~6.67*10^-11 …
Calculate the heat required to raise the temperature of 0.75 kg of ...
2017年1月28日 · This will require 266.9 kJ of heat energy. To calculate the energy required to raise the temperature of any given substance, here's what you require: The mass of the …
What is the average power supplied by a 60.0 kg person ... - Socratic
2016年2月3日 · I found 560W Power is the rate at which work is delivered with time. In this case, the work done by the person will be done against gravity (represented here by the weight of …
How to Calculate the de Broglie wavelength for each of the
2015年4月11日 · To calculate the de Broglie wavelength for a particle, or for a tennis ball for that matter, just use the equation p = h/(lamda), where p - the momentum of the atom; h - Planck's …