2018年3月25日 · Since 6 is essentially #6/1# we know that the slope goes up 6 units. and right 1 unit on a graph. Next, #color(blue)"to find the y-intercept"# of y=6x+1, you substitute x as x=0."# #y=6x+1# #y=6(0)+1# #y=1# #:.# the y-intercept is 1 when x is 0 thus #(0,1)# #color(blue)"To find the x-intercept"# of y=6x+1, you let y=0. #y=6x+1# #0=6x+1# #0-1=6x ...

2016年5月4日 · The proper name for what I am about to show you is the property of being 'distributive'. As a first step example: suppose we had #2(x+5)# then you multiply everything inside the bracket by 2 so you end up with #2x+10#

2015年5月10日 · x^6+1=(x^4-x^2+1)(x^2+1) How did I find this? First of all, substitute x^2 = y to get y^3 + 1. Notice that y = -1 is a solution of y^3+1 = 0, so (y+1) is a factor. We can easily derive y^3+1=(y^2-y+1)(y+1), noticing the way that the intermediate …

2016年8月8日 · x=-1/2 6(x-1)=18x or x-1=(18x)/6 or x-1=3x or 3x-x=-1 or 2x=-1 or x=-1/2. Algebra Properties of Real Numbers When to Use the Distributive Property

2016年5月26日 · It is 9x-7. The rule is that the numbers goes with numbers and the letters goes with the letters. So first of all you can reorder them as 8x+x-6-1. The part with the numbers is easy (only watch out the sign) so you have 8x+x-7. For the letter you have simply to add the numbers in front of the letters. In one case you have the number 8 (for 8x) in the other case it seems …

2015年10月30日 · The zeros mean that we have an exact division In this case (4x^3 +2x-6)/(x-1) =4x^2+6 Suppose we had ended up with a remainder that the x " in " (x-1) could not be divided into. In that case we would express the whole of that remainder as a fraction with (x-1) as the denominator. Suppose that had ended up with a remainder of just 2.

2018年1月23日 · Let #u=x-1# and #v=sqrt(6-x)# #(du)/dx = 1# and #(dv)/dx = -1/2(6-x)^(-1/2)# Plugging this into the formula, you get:

2016年10月5日 · Since a denominator cannot never be zero we have to find the #x# values that make it zero and exclude them from the solutions of the equation. # (x-1)(x+1)=0# This is a product, then it's zero when the factors are zero.

2018年6月5日 · See roots below. x^6-x-1 =0 This degree 6 polynomial will have 6 real and/or complex roots. Using the ...

3(2x + 7) 15 + 6(x+1) can be expanded as 15 + 6x + 6 = 6x + 21 = 3(2x + 7) Do you always have to use the distributive property or can you just divide by the number?