
How do you multiply 0.41 x 3? - Socratic
2016年11月14日 · I got 1.23 We can use our usual algorithm for multiplication putting the numbers in column and multiplying; at the end we have to introduce a decimal point accordingly:
Scientific Notation - Algebra - Socratic
The best videos and questions to learn about Scientific Notation. Get smarter on Socratic.
Rasputin ran part of the way at 8 mph and walked the rest of the …
2018年3月9日 · Rasputin ran 32 miles and walked 9 miles. Let Rasputin ran x miles at 8 mph and walked 41-x miles at 3 mph . He took total 7 hours to complete. Time taken on running is x/8 …
How do you solve 5(x-3)+2x=41? - Socratic
2016年3月27日 · #5x-15+2x=41# We can combine our variables on the left to get #7x-15=41# To get our constants on one side, we can add #15# to both sides. We now have the equation …
How do you solve \sqrt { 2x + 41} - 3= x? - Socratic
2018年3月14日 · x=-8,4 We have: x=sqrt(2x+41)-3 x+3=sqrt(2x+41) (x+3)^2=2x+41 x^2+6x+9=2x+41 x^2+4x-32=0 We can use many methods to solve this. Let's use the …
How do you find all the zeros of f(x) = x^3 + 11x^2 - Socratic
2016年3月21日 · Use the rational root theorem to find zero x = -3, divide by (x+3) then solve the remaining quadratic to find zeros x = -4+-i. f(x) = x^3+11x^2+41x+51 by the rational root …
Systems Using Substitution - Algebra - Socratic
Well, I would say that it is easier when you have few equations and variables. If you have 2 equations and 2 variables it is ok; when you get to 3 equations and 3 variables it becomes …
Simplification of Radical Expressions - Algebra - Socratic
#2/3 root3 (3^3·x^3·x^2) = 2xroot3 (x^2)# I hope you can find it useful, and here is a link to solve this ones with different indices . Sidharth · 1 · Jan 6 2015
How do you find all zeros of F(x)= x^3 -8x^2 +25x -26? - Socratic
2015年9月19日 · There are three solutions: x_0 = 2 x_1 = 3+2i x_2 = 3-2i The rational root theorem tells us that rational roots to a polynomial equation with integer coefficients can be …
How do you find the definite integral of xsqrt(x - 40)dx from [40, …
2016年12月4日 · int_40^41xsqrt(x-40)color(white).dx=406/15 >I=int_40^41xsqrt(x-40)color(white).dx We should apply the substitution u=x-40. This implies that x=u+40 and that …