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How to use "zd" specifier with `printf ()`? - Stack Overflow
2015年10月3日 · The C spec seems to allow printf("%zd\n", sz) depending on how it is read: 7.21.6.1 The fprintf function z Specifies that a following d , i , o , u , x , or X conversion specifier applies to a size_t or the corresponding signed integer type argument; or that a following n conversion specifier applies to a pointer to a signed integer type ...
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Is the %zd specifier an optional feature in C11? [closed]
printf("you entered %zd value of the variable"); Is also undefined behavior because you used a format specifier but didn't pass a matching argument. %zd is a mandatory feature of a hosted implementation of C11. Meaning it is mandatory for any compiler that implements stdio.h. However, %zd doesn't make much sense since size_t is always
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c - Usage of zd vs lu for sizeof - Stack Overflow
2021年1月10日 · I understand that %zd is the suggested way to format the sizeof result. However, I don't understand why that is necessary. However, I don't understand why that is necessary. For example using lu gives me the same output, and isn't the result of …
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