A simple derivation of the Centripetal Acceleration Formula?
2015年7月12日 · Could someone show me a simple and intuitive derivation of the Centripetal Acceleration Formula a = v2 / r, preferably one that does not involve calculus or advanced …
Why do we take $N = mg - mv^2/r$ opposed to $N = mg
2022年4月30日 · So while solving this problem, the solution assumes the normal force to be $$N = mg - mv^2/r$$ But I've learnt that centripetal force isn't any new force and it's an ...
newtonian mechanics - How does $\frac {mv^2} {r} = \frac {GMm} …
2020年9月3日 · How does mv2 r = GMm r2 m v 2 r = G M m r 2 work if both planets attract each other?
Why has $evB$ been equated to $mv^2/R$ here? - Physics Stack …
2020年7月30日 · When 24.8keV 24.8 k e V x-rays strike a material, the photoelectrons emitted from K shell are observed to move in a circle of radius 23mm 23 m m in a magnetic field of 2 × …
newtonian mechanics - Why does solving $\mu mg = m \frac …
2015年6月22日 · For an object to travel at speed v v on a curved path of radius r r, there must a a component of some real force acting sideways on the object. The magnitude of that force …
Centripetal and Gravitational force - Physics Stack Exchange
2017年4月16日 · Your A A must be either m1v2 r m 1 2 r or m2v2 r m 2 2 r and so when put equal to Gm1m2 r2 G m 1 m 2 r 2 one of the masses cancels out.
What is the proof for kinetic energy $= mv^2/2$?
2016年11月17日 · But the WET is derived by knowing that K.E. = 1/2mv2 1 / 2 m v 2. So using the WET to deduce that K.E. = 1/2mv2 1 / 2 m v 2 is a circular argument.
Intuitive explanation for why centripetal acceleration is …
2015年6月21日 · 2)you found out that to differentiate the position vector, you rotate it 90-degrees anti-clock wise to find its direction, for its magnitude, v = rv r v = r v r. 3)you assumed since the …
On the nature of the force $F = \\frac{mv^2}{r}$
2019年1月26日 · I was getting something like this, mv^2÷2 = Ax +C where A and C are constants, I am arbitrarily considering C as zero. Now I get two problems first A is an constant and …
What if, for a body moving in a circle, the centripetal force is not ...
2016年12月26日 · For a particle having a velocity v , the condition for it to move in a circle of radius r is the force on it should be perpendicular to it and equal to mv2 / r