cot is a short way to write 'cotangent'. This is the reciprocal of the trigonometric function 'tangent' or tan(x). Therefore, cot(x) can be simplified to 1/tan(x).

Here we will use: cot(x) = cos(x)/sin(x) cosec 2 (x) = 1 + cot 2 (x). Chain rule : dy/dt * dt/ dx = dy/ dx. Product rule : d/dx (uv) = udv/dx + v*du/dx

For this we have to use trignometric identities, e.g Tan(x)= sin(x)/cos(x), sin 2 (x) + cos 2 (x) = 1, 1/sin(x) = cosec(x)

Find the value of x such that fg(x)=3. Answered by Lutfha A. Find the coordinates of the centre C and the length of the diameter of a circle with the equation (x-2)^2 + (y+5)^2 = 25

Plugging these values into the equation, we want to find Lim((1-cos(x))/sin(x)) as x -> 0. l'Hôpital's rule states that we can differentiate the top and bottom of the fraction separately and the limit will stay the same (note: we are not differentiating the fraction as a whole, this requires the quotient rule, but instead differentiating the ...

cosec(2x) + cot(2x) convert all cosec/cot/sec functions into functions using sin/tan/cos = 1 / (sin2x) + cos(2x) / sin(2x) combine the two fractions into one = [1...

(1) Aim to rearrange the right hand side (rhs) to make it look like the left hand side.LHS = 2 cot (2x) + tan (x)(2) Notice that the rhs is only in terms of x, whereas the right has a function involving 2x.

We also know that we can rewrite the right hand side in terms of sin(x) and cos(x) as follows: cot(x)=1/tan(x) = cos(x)/sin(x). This gives us an idea of what we are trying to make the left hand side look like.

This question makes good use of the trigonometric identities tan 2 x + 1 = sec 2 x and 1 + cot 2 x = cosec 2 x which can be easily recited in the exam by using the identity sin 2 x + cos 2 x = 1 and then dividing by cos 2 x or sin 2 x respectively! Remember, the trick when it comes to solving problems such as these is just perseverance and ...

Substituting these expressions in the numerator and denominator respectively, we get: 1/[(1/2)*sin2x] = 1. Rearranging: sin2x = 2. However, we know that the values of sine are between -1 and 1, hence there is no real value of x such that the equation is verified.