2016年11月14日 · I got 1.23 We can use our usual algorithm for multiplication putting the numbers in column and multiplying; at the end we have to introduce a decimal point accordingly:

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2018年3月9日 · Rasputin ran 32 miles and walked 9 miles. Let Rasputin ran x miles at 8 mph and walked 41-x miles at 3 mph . He took total 7 hours to complete. Time taken on running is x/8 hours and time taken on walking is (41-x)/3 hours . :. x/8+(41 -x)/3=7. Multiplying by 24 on both sides we get , 3x+8(41-x)=7*24 or 3x+328-8x=168 or -5x= 168-328 or 5x=160 :. x=160/5=32 …

2016年3月27日 · #5x-15+2x=41# We can combine our variables on the left to get #7x-15=41# To get our constants on one side, we can add #15# to both sides. We now have the equation #7x=56# Lastly, to completely isolate the variable, we can divide both sides by #7#. We get. #x=8# Hope this helps!

2018年3月14日 · x=-8,4 We have: x=sqrt(2x+41)-3 x+3=sqrt(2x+41) (x+3)^2=2x+41 x^2+6x+9=2x+41 x^2+4x-32=0 We can use many methods to solve this. Let's use the quadratic formula. According to it: x=(-b+-sqrt(b^2-4ac))/(2a) Here, a=1, b=4, c=-32.

2016年3月21日 · Use the rational root theorem to find zero x = -3, divide by (x+3) then solve the remaining quadratic to find zeros x = -4+-i. f(x) = x^3+11x^2+41x+51 by the rational root theorem, any rational zeros of f(x) must be expressible in the form p/q for integers p and q where p is a divisor of the constant term 51 and q a divisor of the coefficient 1 of the leading term. That …

Well, I would say that it is easier when you have few equations and variables. If you have 2 equations and 2 variables it is ok; when you get to 3 equations and 3 variables it becomes more complicated, it is still possible, but you have more work to do. The number of substitutions increases together with the possibility to make mistakes.

#2/3 root3 (3^3·x^3·x^2) = 2xroot3 (x^2)# I hope you can find it useful, and here is a link to solve this ones with different indices . Sidharth · 1 · Jan 6 2015

2015年9月19日 · There are three solutions: x_0 = 2 x_1 = 3+2i x_2 = 3-2i The rational root theorem tells us that rational roots to a polynomial equation with integer coefficients can be written in the form p/q, where p is a factor of the constant term and q is a factor of the leading coefficient. The polynomial equation is 1*x^3 - 8x^2 + 25x - 26 = 0. The integer factors of the constant -26 …

2016年12月4日 · int_40^41xsqrt(x-40)color(white).dx=406/15 >I=int_40^41xsqrt(x-40)color(white).dx We should apply the substitution u=x-40. This implies that x=u+40 and that du=dx. When doing the substitution, plug the current bounds of x=40 and x=41 into u=x-40. These give bounds of x=40=>u=40-40=0 and x=41=>u=41-40=1. Thus: …