
How do you solve (log(35 - x^3))/( log( 5 - Socratic
2016年7月17日 · The soln. is x=3, x=2. We will use these Rules : (R1) : mloga=loga^m (R2) : (a-b)^3=a^3-b^3-3ab(a-b) Now, given that, log(35-x^3)/log(5-x)=3 :. log(35-x^3)=3log(5-x ...
How do you solve for x in log(5-x) - 1/3log(35-x^3)=0? - Socratic
2015年12月6日 · Rearrange and derive a quadratic equation, one of whose roots is a valid solution of the original problem: x = (75-3sqrt(105))/26 ~~ 1.702 Add 1/3 log(35-x^3) to both sides to get: log(5-x) = 1/3 log(35-x^3) Multiply both sides by 3 to get: log(35-x^3) = 3 log(5-x) = log((5-x)^3) Since log is one-one (as a Real valued function), we must have ...
How do you factor x^3 - 2x^2 - 35x? - Socratic
2018年4月8日 · x(x-7)(x+5) First, factor out the GCF (x) x(x^2-2x-35) rarr Now you can use several different methods to factor the x^2-2x-35. You can use the "big X" method, the quadratic formula, or graphing. Here I'll use the "big X" method. Quadratic equation form: ax^2+bx+c Big X method: find two numbers that multiply to a*c, in this case -35 (1*-35) and add up to b, in this …
How do you evaluate the integral #int x^2sqrt(x-3)#? - Socratic
2017年2月11日 · I got: 2/35(x-3)^"3/2"(5x^2 + 12x + 24) + C We don't really like radicals, so let's try letting u = sqrt(x-3). Then: du = 1/(2sqrt(x-3))dx => dx = 2udu (u^2 + 3)^2 = x^2 Therefore, we have: int 2u(u^2+3)^2udu = 2int u^2(u^2+3)^2du = 2int u^2(u^4 + 6u^2 + 9)du = 2int u^6 + 6u^4 + 9u^2du Now this is straightforward to integrate. = 2(u^7/7 + 6/5u^5 + 3u^3) = 2/7 u^7 + …
How do you multiply polynomials #(7x^3 - 6x^2 + 4x-8) (9x^3
2015年10月13日 · Collect the coefficients of the product using a grid to find: (7x^3-6x^2+4x-8)(9x^3-2x^2-3x+5) =63x^6-68x^5+27x^4-27x^3-26x^2+44x-40 One way is to write out a grid of the coefficients and their products as follows: Each reverse diagonal corresponds to choices of terms from each of the two original polynomials that result in the same power of x when …
How do you factor by grouping x^2 + 7x + 5x + 35? | Socratic
2018年4月17日 · #x^2 +7x+5x+35# Matching these equations side by side it is clear that #a=7 and b=5# When they are asking you to (group them) I assume that they are asking you to return them to the original format #(x+a)(x+b)#
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How do you factor 7x+28x^2-35x^3? - Socratic
2017年2月16日 · Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than...
What are the possible rational roots of 6x^4+35x^3-x^2-7x-1
2017年1月9日 · The possible rational roots are +-1;+-1/2;+-1/3;+-1/6; The rational roots are 1/2;-1/3 The possible rational roots are obtained by dividing each of the factors of the known term (-1) by each of the factors of the maximum degree term's coefficient (6). Then they are: +-1;+-1/2;+-1/3;+-1/6 To determine the rational roots, let's use the remainder rule: color(red)(x=1)-> 6+35 …
How do you solve 10x - 3= 35? | Socratic
2018年5月27日 · x = \\frac{38}{10} = \\frac{19}{5} = 3.8 Property of Equality: Adding a number to both sides of a equation will not change the equality: 10x - 3 + 3 = 35 +3 10x = 38 Multiplying a number to both sides of a equation will also not change the equality: 10x * \\frac{1}{10} = 38 * \\frac{1}{10} x = 38 * \\frac{1}{10} x = \\frac{38}{10} = \\frac{19}{5} = 3.8