
How do you solve 2x^2 = 32? - Socratic
2016年1月18日 · x=4 or x=-4 First divide throughout by 2 to get x^2=16 Now take the square root on both sides to get x=+-4. You may now substitute the values of x=4 and x=-4 back into the …
How do you solve #2^x^2 = 32(2^(4x))#? - Socratic
2015年10月26日 · x= 5 or -1 Looking at your format I assume you meant to write: 2^ (x^2) = 32 (2^(4x)) => (2^ (x^2))/(2^(4x)) = 32 => 2^((x^2 - 4x)) = 32 Taking logs: =>(x^2 - 4x)log ...
How do you solve x^2 = 32? - Socratic
2018年3月22日 · x=4sqrt(2)" " Exact answer for principle root x=+-4sqrt(2)" " As a full exact answer x+-5.6569 to 4 decimal places - Approximate answer Consider the 32. We are looking …
How do you find the derivative of 32/x? - Socratic
2016年1月10日 · -32/x^2 Before differentiating this function it requires to be written in the form ax^n note that the derivative of a function must be in the correct form before you can …
How do you solve Log_2 32 = x? - Socratic
2016年3月9日 · x=5 The logarithmic expression can be exponentiated with a base of 2: 2^(log_2 32)=2^x The 2^x and log_2 x functions are inverses, which means that they undo one another, …
How do you factor y= x^2 – 14x – 32? - Socratic
2016年3月21日 · color(blue)((x + 2) ( x -16) is the factorised form of the expression. y = x^2 - 14x - 32 We can Split the Middle Term of this expression to factorise it. In this technique, if we …
How do you factor the trinomial x^2-12x+32? - Socratic
2015年11月23日 · color(blue)((x-4)(x-8) is the factorised form of the expression. x^2-12x+32 We can Split the Middle Term of this expression to factorise it. In this technique, if we have to …
What is the derivative of 32/x? - Socratic
2016年5月20日 · -32/x^2 >Begin by expressing 32/x=32x^-1 differentiate using the color(blue)"power rule" d/dx(ax^n)=nax^(n-1) rArrd/dx(32x^-1)=-1xx32x^-2=-32/x^2
How do you solve 2^ { 2x } - ( 2^ { x + 2} ) - 32= 0? - Socratic
2017年4月29日 · x=3 First of all, you should know that any number of the form a^(bc) can be written in the form (a^b)^c or (a^c)^b or vice-versa. i.e. a^(bc) = (a^b)^c = (a^c)^b. Also, …
How do you find the asymptotes for (x+32)/x^2? - Socratic
2016年3月8日 · Vertical asymptote: x=0 Horizontal asymptote: y=0 To find vertical asymptotes, set the denominator of the function equal to 0. x^2=0 x=0 There is a vertical asymptote at x=0. …