2015年11月26日 · How do you solve #2x = 12#? Algebra Linear Equations One-Step Equations and Inverse Operations. 1 Answer

2015年10月25日 · x=1 First, rearrange the equation like this: 2^(2x) + 2^(x + 2) - 12 = 0 (2^x)^2 + 4(2^x) - 12 = 0 Now, treat this like a quadratic equation by substituting 2^x=s: s^2+4s-12=0 (s+6)(s-2)=0 s=-6 or s=2 Now, go back to the substitution: 2^x=s 2^x=-6 or 2^x=2 Since 2^x can never equal a negative number, we can rule out the first solution. However, the second …

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2016年8月15日 · x= 3 or x = -2 All the numbers in the equation are even, so divide through by 2. x^2 - x - 6 = 0" find factors" The factors of 6 which subtract to make 1 are 2 and 2.

2016年6月29日 · 2(x - x1)(x - x2) y = 2x^2 + 3x - 12 Factored form of y: y = a(x - x1)(x - x2) Find x1 and x2, the 2 real roots of y.

2015年9月11日 · The slope is -2/3. Convert the given equation to the slope-intercept form by solving for y. 2x+3y=12 is the standard form for a linear equation. To determine the slope, solve the equation for y in order to convert to the slope-intercept form y=mx+b, where m is the slope and b is the y-intercept. 2x+3y=12 Subtract 2x from both sides. 3y=-2x+12 Divide both sides …

2016年3月7日 · slope = 2/3 , intercept = -4 >One form of the equation of a line is y = mx + c , where m represents the gradient (slope) and c , the y-intercept.

2018年3月3日 · x = 7, -2 |2x - 5| + 3 = 12 Given Equation |2x - 5| = 9 Subtracted 3 from both sides |2x| = 14 Added 5 to each side. x = 7 Divided 2 by both sides Since this is absolute value, you are also required to also solve the equation where in this case x could also be negative aswell as positive. -|2x - 5| + 3 = 12 -2x + 5 + 3 = 12 Distributed the negative sign. -2x + 8 = 12 Added 5 …

2018年3月20日 · By rebuilding it to an easier formula. This formula can be "rebuild" into the regular form of y = a*x + b We substract 2x from each side of the equation, we then get; 3y = -2x + 12 We then divide everything by 3. The formula then looks like this; y = (-2/3 * x) + 12, which you should be able to graph.

2015年2月3日 · We can use the Sum-Product method. Bring everything to one side: x^2-x=12->x^2-x-12=0 We now have a quadratic equation of the form ax^2+bx+c=0 where a=1, b=-1 and c=-12 We find two numbers that will give c=-12 as a product and b=-1 as a sum (or difference). We can try 1*12, 2*6,3*4 3and4 will fit, with a -sign to the 4, as that would make the sum 3-4= …