
How do you factor #a^2 - 2ab +b^2# - Socratic
2018年3月4日 · (a - b)^2 Break down the expression into a simpler form by regrouping and putting brackets. a^2 - 2ab +b^2 a^2 - ab - ab +b^2 a(a - b) - b(a - b) (a - b) (a - b) (a - b)^2
Why does (A+B)^2 = A^2+2AB+B^2 not work for matrices?
2018年2月19日 · Why does #(A+B)^2 = A^2+2AB+B^2# not work for matrices? Precalculus. 1 Answer George C. Feb 19, 2018 ...
If (a^2-b^2)sintheta + 2ab costheta = a^2+b^2, then what
2016年11月27日 · If #(a^2-b^2)sintheta + 2ab costheta = a^2+b^2#, then what will the value of #sintheta# be? Trigonometry Trigonometric Identities and Equations Proving Identities 2 Answers
Classifying reactions? - Socratic
2018年2月24日 · Endothermic Exothermic Endothermic Endothermic Exothermic The stronger the bond, the more the energy required to break it, similarly the stronger the bond formed, the more energy released. 1.A-B, being a strong bond requires more energy to break it then, the formation of the weak bond of AC which releases very little energy, so the reaction is relatively endothermic, as more energy is absorbed ...
How do you solve x^2(a^2+2ab+b^2) = x(a+b) by factoring?
2015年8月21日 · First, notice that you can write #(a^2 + 2ab + b^2)# as the square of #(a + b)#. #a^2 + 2ab + b^2 = (a + b)^2# ...
Show that if A and B are square matrices such that - Socratic
2018年3月4日 · #=A^2+2AB+B^2#, as desired! Answer link. Related questions. How do I determine the molecular shape of a ...
How do you factor #a² + 2ab + b² - x² - 6x - 9#? - Socratic
2016年5月20日 · (a+b+x+3)(a+b-x-3). Use A^2-B^3=(A+B)(A-B) The expression is (a+b)^2-(x+3)^2 (a+b+x+3)(a+b-x-3). How do you find the two numbers by using the factoring method, if one number is seven more than...
If a^2 + b^2 = 4 and (a-b)^2 =2, what is the value of ab? - Socratic
2018年3月30日 · It follows that a^2 + b^2 = 2 + 2ab, and since we're given that a^2+ b^2 = 4, we can say 4 = 2 + 2ab. Doing a little algebra we get 4 = 2(1 + ab) 2 = 1 + ab ab = 1 Hopefully this helps! Algebra
How do you factor a^2 - 4ab + 4b^2? - Socratic
2016年5月14日 · #a^2 - 4ab + 4 b ^2# We can Split the Middle Term of this expression to factorise it.. #a^2 - color(blue)(4ab) + 4 b ^2#
How do you find the product (a-2b)^2? - Socratic
2017年4月5日 · a^2-4ab+4b^2 Note: (a-2b)^2=(a-2b)(a-2b) Each term in the second bracket must be multiplied by each term in the first bracket. This is shown below. (color(red)(a-2b))(a-2b) =color(red)(a)(a-2b)color(red)(-2b)(a-2b) distribute and collect like terms. =a^2color(magenta)(-2ab)color(magenta)(-2ab)+4b^2 =a^2-4ab+4b^2