Therefore since the trig equation we are solving is sin and it ... and the other between \(270^\circ\) and \(360^\circ\). \(\sin x^\circ = - 0.349\) Since this is sin, but negative this means ...

sin x^\circ = 0.5\) \(x^\circ = {\sin ^{ - 1 ... Therefore since the trig equation we are solving is sin and it is positive (0.5), then we are in the first and second quadrants.