The graph of \(y = x^2 - 6x + 9 \) touches the x-axis at \( x = 3\). It is not possible to find the square root of a negative number, so the equation has no solutions. The graph of \(y = x^2 + 2x ...

{2 \times 1} = \frac{-2\pm \sqrt{-16}}{2 \times 1}\) It is not possible to find the square root of a negative number, so the equation has no solutions. The graph of \(y = x^2 + 2x + 5\) does not ...

[MindYourDecisions] presents a Babylonian tablet dating back to around 1800 BC that shows that the hypotenuse of a unit square is the square root of two or 1.41421. How did they know that?